What is the answer to solvefor u,log_{u}(15/16)=v ?

The answer to solvefor u,log_{u}(15/16)=v is u=e^{(ln(15/16))/v} {v 0}

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solvefor u,log_{u}(15/16)=v

solve for

u, lo g_{u} (\frac{15}{16}) = v

u = e^{\frac{l n ( \frac{15}{16} )}{v}} {v < 0 or v > 0}

Solution steps

lo g_{u} (\frac{15}{16}) = v

Apply log rules

\frac{ln ( \frac{15}{16} )}{ln ( u )} = v

Multiply both sides by

ln (u)

\frac{ln ( \frac{15}{16} )}{ln ( u )} ln (u) = v ln (u)

Simplify

ln (\frac{15}{16}) = v ln (u)

Switch sides

v ln (u) = ln (\frac{15}{16})

Divide both sides by

v

ln (u) = \frac{ln ( \frac{15}{16} )}{v}

Apply log rules

u = e^{\frac{l n ( \frac{15}{16} )}{v}}

Verify Solutions:

u = e^{\frac{l n ( \frac{15}{16} )}{v}} {v < 0 or v > 0}

The solution is

u = e^{\frac{l n ( \frac{15}{16} )}{v}} {v < 0 or v > 0}

lo g_{2} (6 \cdot 2^{2 n + 1} - 6) = n

lo g_{10} (x) - lo g_{10} (9) = 1

6.7 = lo g_{10} (\frac{I}{1})

lo g_{9} (x) = 5

lo g_{10} (- \frac{1}{3} x) + 1 = 0

What is the answer to solvefor u,log_{u}(15/16)=v ?
The answer to solvefor u,log_{u}(15/16)=v is u=e^{(ln(15/16))/v} {v<0\lor v>0}