What is the answer to log_{2}(x)=(ln(x))/(ln(2)) ?

The answer to log_{2}(x)=(ln(x))/(ln(2)) is x>0

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log_{2}(x)=(ln(x))/(ln(2))

lo g_{2} (x) = \frac{ln ( x )}{ln ( 2 )}

x > 0

Solution steps

lo g_{2} (x) = \frac{ln ( x )}{ln ( 2 )}

Multiply both sides by

ln (2)

lo g_{2} (x) ln (2) = \frac{ln ( x )}{ln ( 2 )} ln (2)

Apply log rules

x = x

Both sides are equal

True for all x

Verify Solutions:

x > 0

The solution is

x > 0

ln (- 7 x - 4) = 3

lo g_{\frac{1}{3}} (4 + 5 x) = - 2

lo g_{2} (3 x + 2) = 4

0 = - 6 lo g_{9} (x + 9)

lo g_{2 x} (3 x^{2} + 4 x - 3) = 2

What is the answer to log_{2}(x)=(ln(x))/(ln(2)) ?
The answer to log_{2}(x)=(ln(x))/(ln(2)) is x>0
Solve for x: log_{2}(x)=(ln(x))/(ln(2))
The solution is x>0