What is the answer to log_{6}(2x-5)+4=18 ?

The answer to log_{6}(2x-5)+4=18 is x=(6^{14}+5)/2

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log_{6}(2x-5)+4=18

lo g_{6} (2 x - 5) + 4 = 18

x = \frac{6 ^{14} + 5}{2}

Decimal

x = 39182082050.5

Solution steps

lo g_{6} (2 x - 5) + 4 = 18

Move

4

to the right side

lo g_{6} (2 x - 5) = 14

Apply log rules

2 x - 5 = 6^{14}

Solve

2 x - 5 = 6^{14} : x = \frac{6 ^{14} + 5}{2}

x = \frac{6 ^{14} + 5}{2}

Verify Solutions:

x = \frac{6 ^{14} + 5}{2}

True

The solution is

x = \frac{6 ^{14} + 5}{2}

lo g_{7} (x - 9) = 2

lo g_{3} (5 + x) = 4

lo g_{2} (x^{2}) + 4 = 10

ln (x + 2) + ln (x) = ln (24)

ln (x^{2}) - 0.7

What is the answer to log_{6}(2x-5)+4=18 ?
The answer to log_{6}(2x-5)+4=18 is x=(6^{14}+5)/2
Solve for x: log_{6}(2x-5)+4=18
The solution is x=(6^{14}+5)/2