What is the answer to 3(2xln(x^2)+2x)=0 ?

The answer to 3(2xln(x^2)+2x)=0 is x=sqrt(1/e),x=-sqrt(1/e)

Solve for x: 3(2xln(x^2)+2x)=0

The solution is x=sqrt(1/e),x=-sqrt(1/e)

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3 (2 x ln (x^{2}) + 2 x) = 0

x = \frac{1}{e}, x = - \frac{1}{e}

Decimal

x = 0.60653 \dots, x = - 0.60653 \dots

Solution steps

3 (2 x ln (x^{2}) + 2 x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x ln (x^{2}) + 2 x = 0

Solve

2 x ln (x^{2}) + 2 x = 0 : x = \frac{1}{e}, x = - \frac{1}{e}

Verify Solutions:

x = \frac{1}{e}

True

, x = - \frac{1}{e}

True

The solutions are

x = \frac{1}{e}, x = - \frac{1}{e}

ln (x) = 3 - x

lo g_{7} (2 x^{2} - 5 x) = 1

lo g_{12} (x^{2} - 8 x + 16) = 0

lo g_{10} (x) 16 = 2

lo g_{x} (9) = 0.5

What is the answer to 3(2xln(x^2)+2x)=0 ?
The answer to 3(2xln(x^2)+2x)=0 is x=sqrt(1/e),x=-sqrt(1/e)
Solve for x: 3(2xln(x^2)+2x)=0
The solution is x=sqrt(1/e),x=-sqrt(1/e)