What is the answer to 9log_{4}(10x+4)=27 ?

The answer to 9log_{4}(10x+4)=27 is x=6

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9log_{4}(10x+4)=27

9 lo g_{4} (10 x + 4) = 27

x = 6

Solution steps

9 lo g_{4} (10 x + 4) = 27

Divide both sides by

9

lo g_{4} (10 x + 4) = 3

Apply log rules

10 x + 4 = 64

Solve

10 x + 4 = 64 : x = 6

x = 6

Verify Solutions:

x = 6

True

The solution is

x = 6

lo g_{5} (- 8 x - 3) = 1

lo g_{10} (x^{2}) = 6

lo g_{10} (x) + lo g_{10} (2) = 3

ln (3 x + 2) = 4

lo g_{3} (x) + lo g_{9} (x) = 10

What is the answer to 9log_{4}(10x+4)=27 ?
The answer to 9log_{4}(10x+4)=27 is x=6
Solve for x: 9log_{4}(10x+4)=27
The solution is x=6