What is the answer to ln((x-4)^2)=12 ?

The answer to ln((x-4)^2)=12 is x=e^6+4,x=-e^6+4

Solve for x: ln((x-4)^2)=12

The solution is x=e^6+4,x=-e^6+4

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ln ((x - 4)^{2}) = 12

x = e^{6} + 4, x = - e^{6} + 4

Decimal

x = 407.42879 \dots, x = - 399.42879 \dots

Solution steps

ln ((x - 4)^{2}) = 12

Apply log rules

(x - 4)^{2} = e^{12}

Solve

(x - 4)^{2} = e^{12} : x = e^{6} + 4, x = - e^{6} + 4

x = e^{6} + 4, x = - e^{6} + 4

lo g_{2 x - 2} (3 x^{2} + 2 x - 17) = 2

lo g_{10} (3 x + 1) = 6

ln (x + 5) = 1

lo g_{5} (x^{2} + 5) = 3

lo g_{3} (a) = 4

What is the answer to ln((x-4)^2)=12 ?
The answer to ln((x-4)^2)=12 is x=e^6+4,x=-e^6+4
Solve for x: ln((x-4)^2)=12
The solution is x=e^6+4,x=-e^6+4