What is the answer to 3-4log_{2}(3x+4)=19 ?

The answer to 3-4log_{2}(3x+4)=19 is x=-21/16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3-4log_{2}(3x+4)=19

3 - 4 lo g_{2} (3 x + 4) = 19

x = - \frac{21}{16}

Decimal

x = - 1.3125

Solution steps

3 - 4 lo g_{2} (3 x + 4) = 19

Move

3

to the right side

- 4 lo g_{2} (3 x + 4) = 16

Divide both sides by

- 4

lo g_{2} (3 x + 4) = - 4

Apply log rules

3 x + 4 = \frac{1}{16}

Solve

3 x + 4 = \frac{1}{16} : x = - \frac{21}{16}

x = - \frac{21}{16}

Verify Solutions:

x = - \frac{21}{16}

True

The solution is

x = - \frac{21}{16}

lo g_{x} (6) = 2

lo g_{3} (x + 3) = - 2

ln (x) = \frac{e}{e - 1} - 1

2 ln (x) = ln (25)

lo g_{2} ((x - 3)^{3}) = 6

What is the answer to 3-4log_{2}(3x+4)=19 ?
The answer to 3-4log_{2}(3x+4)=19 is x=-21/16
Solve for x: 3-4log_{2}(3x+4)=19
The solution is x=-21/16