What is the answer to log_{2}(4x+3)=3 ?

The answer to log_{2}(4x+3)=3 is x= 5/4

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log_{2}(4x+3)=3

lo g_{2} (4 x + 3) = 3

x = \frac{5}{4}

Decimal

x = 1.25

Solution steps

lo g_{2} (4 x + 3) = 3

Apply log rules

4 x + 3 = 8

Solve

4 x + 3 = 8 : x = \frac{5}{4}

x = \frac{5}{4}

m, lo g (m) = 6 lo g (n)

3 lo g_{3} (x) = 9

4 - 6 lo g_{10} (3 x - 1) = - 20

ln (\frac{x}{4}) + 1 = 0

lo g_{5} (x^{2}) = 0