What is the answer to log_{4}(x^2-5x-13)=0 ?

The answer to log_{4}(x^2-5x-13)=0 is x=7,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{4}(x^2-5x-13)=0

lo g_{4} (x^{2} - 5 x - 13) = 0

x = 7, x = - 2

Solution steps

lo g_{4} (x^{2} - 5 x - 13) = 0

Apply log rules

x^{2} - 5 x - 13 = 1

Solve

x^{2} - 5 x - 13 = 1 : x = 7, x = - 2

x = 7, x = - 2

11 = - lo g_{10} (x)

3 lo g_{4} (x + 2) = 5

lo g_{2} (1 - x) = 3

lo g_{10} (x) = 1 + lo g_{10} (22 - x)

ln (x) + ln (3) = 5

What is the answer to log_{4}(x^2-5x-13)=0 ?
The answer to log_{4}(x^2-5x-13)=0 is x=7,x=-2
Solve for x: log_{4}(x^2-5x-13)=0
The solution is x=7,x=-2