What are the solutions to the equation 4x^2+4x-24=0 ?

The solutions to the equation 4x^2+4x-24=0 are x=2,x=-3

Find the zeros of 4x^2+4x-24=0

The zeros of 4x^2+4x-24=0 are x=2,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 4 x - 24 = 0

x = 2, x = - 3

Solution steps

4 x^{2} + 4 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 24 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 24) = 20

x_{1, 2} = \frac{- 4 \pm 20}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 20}{2 \cdot 4}, x_{2} = \frac{- 4 - 20}{2 \cdot 4}

x = \frac{- 4 + 20}{2 \cdot 4} : 2

x = \frac{- 4 - 20}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

\frac{1}{- 0.5}

3 (2 x - 5) = 9 (10 - x)

\frac{4}{3} \cdot 1

2 x^{3} x^{3}

9 j^{2} - 25

What are the solutions to the equation 4x^2+4x-24=0 ?
The solutions to the equation 4x^2+4x-24=0 are x=2,x=-3
Find the zeros of 4x^2+4x-24=0
The zeros of 4x^2+4x-24=0 are x=2,x=-3