What is the answer to 5log_{3}(x+1)+6=7 ?

The answer to 5log_{3}(x+1)+6=7 is x=\sqrt[5]{3}-1

Solve for x: 5log_{3}(x+1)+6=7

The solution is x=\sqrt[5]{3}-1

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5 lo g_{3} (x + 1) + 6 = 7

x = 53 - 1

Decimal

x = 0.24573 \dots

Solution steps

5 lo g_{3} (x + 1) + 6 = 7

Move

6

to the right side

5 lo g_{3} (x + 1) = 1

Divide both sides by

5

lo g_{3} (x + 1) = \frac{1}{5}

Apply log rules

x + 1 = 53

Solve

x + 1 = 53 : x = 53 - 1

x = 53 - 1

Verify Solutions:

x = 53 - 1

True

The solution is

x = 53 - 1

lo g_{x} (4) = \frac{- 2}{5}

2 lo g_{10} (7 x) + 1 = 4

20 lo g_{10} (x) = - 6.628

lo g_{6} (x^{2} - x) = 1

5 ln (x) = - 10

What is the answer to 5log_{3}(x+1)+6=7 ?
The answer to 5log_{3}(x+1)+6=7 is x=\sqrt[5]{3}-1
Solve for x: 5log_{3}(x+1)+6=7
The solution is x=\sqrt[5]{3}-1