What is the answer to log_{2}(x^2)-4=0 ?

The answer to log_{2}(x^2)-4=0 is x=4,x=-4

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log_{2}(x^2)-4=0

lo g_{2} (x^{2}) - 4 = 0

x = 4, x = - 4

Solution steps

lo g_{2} (x^{2}) - 4 = 0

Move

4

to the right side

lo g_{2} (x^{2}) = 4

Apply log rules

x^{2} = 16

Solve

x^{2} = 16 : x = 4, x = - 4

x = 4, x = - 4

Verify Solutions:

x = 4

True

, x = - 4

True

The solutions are

x = 4, x = - 4

lo g_{2} (x + 10) = 8

lo g_{10} (5 x) + lo g_{10} (3 x) = 1

4 ln (5 x - 8) - 14 = - 2

5.74 = 4.8 + lo g_{10} (\frac{x}{0.05})

3 \times lo g_{2} (x - 2) = 12

What is the answer to log_{2}(x^2)-4=0 ?
The answer to log_{2}(x^2)-4=0 is x=4,x=-4
Solve for x: log_{2}(x^2)-4=0
The solution is x=4,x=-4