What is the answer to log_{10}(sqrt(7))= 3/4 log_{10}(49)-log_{10}(x) ?

The answer to log_{10}(sqrt(7))= 3/4 log_{10}(49)-log_{10}(x) is x=7

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log_{10}(sqrt(7))= 3/4 log_{10}(49)-log_{10}(x)

lo g_{10} (7) = \frac{3}{4} lo g_{10} (49) - lo g_{10} (x)

x = 7

Solution steps

lo g_{10} (7) = \frac{3}{4} lo g_{10} (49) - lo g_{10} (x)

Move

lo g_{10} (x)

to the left side

lo g_{10} (7) + lo g_{10} (x) = \frac{3}{4} lo g_{10} (49)

Move

lo g_{10} (7)

to the right side

lo g_{10} (x) = \frac{3}{4} lo g_{10} (49) - lo g_{10} (7)

Apply log rules

x = 7

Verify Solutions:

x = 7

True

The solution is

x = 7

lo g_{x} (\frac{1}{1296}) = 4

lo g_{x} (729) = \frac{3}{2}

lo g_{10} (x) = - \frac{5}{7}

lo g_{2} (6 x + 2) = 4

lo g_{- 2} (x) = 3

What is the answer to log_{10}(sqrt(7))= 3/4 log_{10}(49)-log_{10}(x) ?
The answer to log_{10}(sqrt(7))= 3/4 log_{10}(49)-log_{10}(x) is x=7
Solve for x: log_{10}(sqrt(7))= 3/4 log_{10}(49)-log_{10}(x)
The solution is x=7