What is the answer to log_{10}(x^2)=log_{10}(10)+log_{10}(x)-log_{10}(9)+log_{10}(10) ?

The answer to log_{10}(x^2)=log_{10}(10)+log_{10}(x)-log_{10}(9)+log_{10}(10) is x= 100/9

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log_{10}(x^2)=log_{10}(10)+log_{10}(x)-log_{10}(9)+log_{10}(10)

lo g_{10} (x^{2}) = lo g_{10} (10) + lo g_{10} (x) - lo g_{10} (9) + lo g_{10} (10)

x = \frac{100}{9}

Decimal

x = 11.11111 \dots

Solution steps

lo g_{10} (x^{2}) = lo g_{10} (10) + lo g_{10} (x) - lo g_{10} (9) + lo g_{10} (10)

Apply log rules

x = \frac{100}{9}

Verify Solutions:

x = \frac{100}{9}

True

The solution is

x = \frac{100}{9}

0 = 12 x^{2} ln (x) + 7 x^{2}

x^{3} + 4 x^{3} ln (x) = 0

lo g_{10} (2 x - 5) = 0

lo g_{0.2} (3 x - 1) = - 3

lo g_{\frac{1}{4}} (x + 4) = - 1

What is the answer to log_{10}(x^2)=log_{10}(10)+log_{10}(x)-log_{10}(9)+log_{10}(10) ?
The answer to log_{10}(x^2)=log_{10}(10)+log_{10}(x)-log_{10}(9)+log_{10}(10) is x= 100/9
Solve for x: log_{10}(x^2)=log_{10}(10)+log_{10}(x)-log_{10}(9)+log_{10}(10)
The solution is x= 100/9