What is the answer to log_{x}(\sqrt[3]{36})=2 ?

The answer to log_{x}(\sqrt[3]{36})=2 is x=e^{(ln(6))/3}

Solve for x: log_{x}(\sqrt[3]{36})=2

The solution is x=e^{(ln(6))/3}

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lo g_{x} (336) = 2

x = e^{\frac{l n ( 6 )}{3}}

Decimal

x = 1.81712 \dots

Solution steps

lo g_{x} (336) = 2

Apply log rules

\frac{ln ( 3 36 )}{ln ( x )} = 2

Multiply both sides by

ln (x)

\frac{ln ( 3 36 )}{ln ( x )} ln (x) = 2 ln (x)

Apply log rules

x = e^{\frac{l n ( 6 )}{3}}

Verify Solutions:

x = e^{\frac{l n ( 6 )}{3}}

True

The solution is

x = e^{\frac{l n ( 6 )}{3}}

lo g_{7} (3 - x) = 2 lo g_{7} (4)

lo g_{10} (a) = 4

lo g_{10} (x) = 40.92

lo g_{\frac{1}{3}} (4 x - 5) = - 2

3 lo g_{2} (x + 4) = 9

What is the answer to log_{x}(\sqrt[3]{36})=2 ?
The answer to log_{x}(\sqrt[3]{36})=2 is x=e^{(ln(6))/3}
Solve for x: log_{x}(\sqrt[3]{36})=2
The solution is x=e^{(ln(6))/3}