What is the answer to log_{x}(3)=41 ?

The answer to log_{x}(3)=41 is x=\sqrt[41]{3}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{x}(3)=41

lo g_{x} (3) = 41

x = 413

Decimal

x = 1.02715 \dots

Solution steps

lo g_{x} (3) = 41

Apply log rules

\frac{1}{lo g _{3} ( x )} = 41

Multiply both sides by

lo g_{3} (x)

\frac{1}{lo g _{3} ( x )} lo g_{3} (x) = 41 lo g_{3} (x)

Simplify

1 = 41 lo g_{3} (x)

Switch sides

41 lo g_{3} (x) = 1

Divide both sides by

41

lo g_{3} (x) = \frac{1}{41}

Apply log rules

x = 413

Verify Solutions:

x = 413

True

The solution is

x = 413

lo g_{b} (16) = - 4

lo g_{10} (5 x) = 6

lo g_{7} (x^{2} - x + 1) = 1

0 = (ln (x))^{2}

lo g_{10} (x - 3) = 1 - lo g_{10} (x)

What is the answer to log_{x}(3)=41 ?
The answer to log_{x}(3)=41 is x=\sqrt[41]{3}
Solve for x: log_{x}(3)=41
The solution is x=\sqrt[41]{3}