What is the answer to 1/(2log_{10)(2x-1)+2}=5 ?

The answer to 1/(2log_{10)(2x-1)+2}=5 is x=(1+10^{9/10})/(2*10^{9/10)}

Solve for x: 1/(2log_{10)(2x-1)+2}=5

The solution is x=(1+10^{9/10})/(2*10^{9/10)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{1}{2 lo g _{10} ( 2 x - 1 ) + 2} = 5

x = \frac{1 + 1 0 ^{\frac{9}{10}}}{2 \cdot 1 0 ^{\frac{9}{10}}}

Decimal

x = 0.56294 \dots

Solution steps

\frac{1}{2 lo g _{10} ( 2 x - 1 ) + 2} = 5

Rewrite the equation with

lo g_{10} (2 x - 1) = u

\frac{1}{2 u + 2} = 5

Solve

\frac{1}{2 u + 2} = 5 : u = - \frac{9}{10}

u = - \frac{9}{10}

Substitute back

u = lo g_{10} (2 x - 1),

solve for

x

Solve

lo g_{10} (2 x - 1) = - \frac{9}{10} : x = \frac{1 + 1 0 ^{\frac{9}{10}}}{2 \cdot 1 0 ^{\frac{9}{10}}}

x = \frac{1 + 1 0 ^{\frac{9}{10}}}{2 \cdot 1 0 ^{\frac{9}{10}}}

Verify Solutions:

x = \frac{1 + 1 0 ^{\frac{9}{10}}}{2 \cdot 1 0 ^{\frac{9}{10}}}

True

The solution is

x = \frac{1 + 1 0 ^{\frac{9}{10}}}{2 \cdot 1 0 ^{\frac{9}{10}}}

5 lo g_{x} (16) = 10

3 lo g_{8} (x) = 1

lo g_{10} (x) (\frac{1}{27}) = - 3

lo g_{10} (x) + lo g_{10} (20) = 3

\frac{1}{2} = lo g_{10} (x)

What is the answer to 1/(2log_{10)(2x-1)+2}=5 ?
The answer to 1/(2log_{10)(2x-1)+2}=5 is x=(1+10^{9/10})/(2*10^{9/10)}
Solve for x: 1/(2log_{10)(2x-1)+2}=5
The solution is x=(1+10^{9/10})/(2*10^{9/10)}