What are the solutions to the equation 7k^2-6k+3=3 ?

The solutions to the equation 7k^2-6k+3=3 are k= 6/7 ,k=0

Find the zeros of 7k^2-6k+3=3

The zeros of 7k^2-6k+3=3 are k= 6/7 ,k=0

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7 k^{2} - 6 k + 3 = 3

k = \frac{6}{7}, k = 0

Solution steps

7 k^{2} - 6 k + 3 = 3

Move

3

to the left side

7 k^{2} - 6 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 7 \cdot 0}{2 \cdot 7}

(- 6)^{2} - 4 \cdot 7 \cdot 0 = 6

k_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 7}

Separate the solutions

k_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 7}, k_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 7}

k = \frac{- ( - 6 ) + 6}{2 \cdot 7} : \frac{6}{7}

k = \frac{- ( - 6 ) - 6}{2 \cdot 7} : 0

The solutions to the quadratic equation are:

k = \frac{6}{7}, k = 0

5 x^{2} - 5 x - 10

5^{∣ 4 x - 6 ∣} = 2 5^{3 x - 4}

x^{3} < 100 x

5 x^{2} + 12 x - 9 < 0

a^{3} + 5 a^{2} + a + 5

What are the solutions to the equation 7k^2-6k+3=3 ?
The solutions to the equation 7k^2-6k+3=3 are k= 6/7 ,k=0
Find the zeros of 7k^2-6k+3=3
The zeros of 7k^2-6k+3=3 are k= 6/7 ,k=0