What is the answer to log_{10}(x+2)=2-x ?

The answer to log_{10}(x+2)=2-x is x=(\W_{0}(10000ln(10)))/(ln(10))-2

Solve for x: log_{10}(x+2)=2-x

The solution is x=(\W_{0}(10000ln(10)))/(ln(10))-2

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lo g_{10} (x + 2) = 2 - x

x = \frac{W _{0} ( 10000 ln ( 10 ) )}{ln ( 10 )} - 2

Decimal

x = 1.46082 \dots

Solution steps

lo g_{10} (x + 2) = 2 - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (x + 2)} = 1 0^{2 - x}

Simplify

1 0^{l o g_{10} (x + 2)} : x + 2

x + 2 = 1 0^{2 - x}

Solve

x + 2 = 1 0^{2 - x} : x = \frac{W _{0} ( 10000 ln ( 10 ) )}{ln ( 10 )} - 2

x = \frac{W _{0} ( 10000 ln ( 10 ) )}{ln ( 10 )} - 2

Verify Solutions:

x = \frac{W _{0} ( 10000 ln ( 10 ) )}{ln ( 10 )} - 2

True

The solution is

x = \frac{W _{0} ( 10000 ln ( 10 ) )}{ln ( 10 )} - 2

lo g_{b} (b) = 1

ln (x) - ln (3) = ln (15)

lo g_{4 x + 1} (9 x) = - 1

- 2 ln (x) - 1 = 0

lo g_{6} (x - 3) = 2

What is the answer to log_{10}(x+2)=2-x ?
The answer to log_{10}(x+2)=2-x is x=(\W_{0}(10000ln(10)))/(ln(10))-2
Solve for x: log_{10}(x+2)=2-x
The solution is x=(\W_{0}(10000ln(10)))/(ln(10))-2