What is the answer to log_{2}(x^2+3x-3)=0 ?

The answer to log_{2}(x^2+3x-3)=0 is x=1,x=-4

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log_{2}(x^2+3x-3)=0

lo g_{2} (x^{2} + 3 x - 3) = 0

x = 1, x = - 4

Solution steps

lo g_{2} (x^{2} + 3 x - 3) = 0

Apply log rules

x^{2} + 3 x - 3 = 1

Solve

x^{2} + 3 x - 3 = 1 : x = 1, x = - 4

x = 1, x = - 4

lo g_{4} (x + 1) = 1

x, ln (u) = - ln (x)

lo g_{10} (x) = - 4.7

lo g_{3} (x) = 2 lo g_{9} (6) - lo g_{9} (12)

26 = 20 lo g_{10} (\frac{10000}{x})

What is the answer to log_{2}(x^2+3x-3)=0 ?
The answer to log_{2}(x^2+3x-3)=0 is x=1,x=-4
Solve for x: log_{2}(x^2+3x-3)=0
The solution is x=1,x=-4