What are the solutions to the equation 4(2x-8)^2-45=-21 ?

The solutions to the equation 4(2x-8)^2-45=-21 are x=(sqrt(6)+8)/2 ,x=(-sqrt(6)+8)/2

Find the zeros of 4(2x-8)^2-45=-21

The zeros of 4(2x-8)^2-45=-21 are x=(sqrt(6)+8)/2 ,x=(-sqrt(6)+8)/2

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4 (2 x - 8)^{2} - 45 = - 21

x = \frac{6 + 8}{2}, x = \frac{- 6 + 8}{2}

Solution steps

4 (2 x - 8)^{2} - 45 = - 21

Move

45

to the right side

4 (2 x - 8)^{2} = 24

Divide both sides by

4

(2 x - 8)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 8 = 6 : x = \frac{6 + 8}{2}

Solve

2 x - 8 = - 6 : x = \frac{- 6 + 8}{2}

The solutions to the quadratic equation are:

x = \frac{6 + 8}{2}, x = \frac{- 6 + 8}{2}

- 4 + \frac{1}{2} x = 8

\frac{2}{3864 ( 3.05 )}

\frac{x}{y ^{2}} - \frac{x ^{2}}{y ^{2}}

6 x^{2} - 100 = 0

∣ 2 x - 1 ∣ > 5

What are the solutions to the equation 4(2x-8)^2-45=-21 ?
The solutions to the equation 4(2x-8)^2-45=-21 are x=(sqrt(6)+8)/2 ,x=(-sqrt(6)+8)/2
Find the zeros of 4(2x-8)^2-45=-21
The zeros of 4(2x-8)^2-45=-21 are x=(sqrt(6)+8)/2 ,x=(-sqrt(6)+8)/2