What is the answer to e^{ln(x^x)}=x^2 ?

The answer to e^{ln(x^x)}=x^2 is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

e^{ln(x^x)}=x^2

e^{l n (x^{x})} = x^{2}

No Solution for x \in R

Solution steps

e^{l n (x^{x})} = x^{2}

Take both sides of the equation to the power of

\frac{1}{2}

(e^{l n (x^{x})})^{\frac{1}{2}} = (x^{2})^{\frac{1}{2}}

Simplify

(e^{l n (x^{x})})^{\frac{1}{2}} : (x^{x})^{\frac{1}{2}}

Simplify

(x^{2})^{\frac{1}{2}} : ∣ x ∣

Solve

(x^{x})^{\frac{1}{2}} = ∣ x ∣ :

No Solution for

x \in R

No Solution for x \in R

lo g_{10} (x) = lo g_{10} (6) - lo g_{10} (5) + 1

lo g_{2} (x) - lo g_{2} (x - 1) = 2

ln (x) - 6 x^{2} ln (x) = - 5 x ln (x)

x, y^{2} + ln (x y) = 2

3 lo g_{2} (x) = 5

What is the answer to e^{ln(x^x)}=x^2 ?
The answer to e^{ln(x^x)}=x^2 is No Solution for x\in\mathbb{R}