What is the answer to log_{2}(x^2-7x)=3 ?

The answer to log_{2}(x^2-7x)=3 is x=8,x=-1

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log_{2}(x^2-7x)=3

lo g_{2} (x^{2} - 7 x) = 3

x = 8, x = - 1

Solution steps

lo g_{2} (x^{2} - 7 x) = 3

Apply log rules

x^{2} - 7 x = 8

Solve

x^{2} - 7 x = 8 : x = 8, x = - 1

x = 8, x = - 1

ln (2 x) = 2 + ln (x - 1)

lo g_{7} (x - 5) + 5 = 7

12 x ln (x) + 6 x = 0

6 + lo g_{8} (- 2 x) = 5

lo g_{x} (2) = 8

What is the answer to log_{2}(x^2-7x)=3 ?
The answer to log_{2}(x^2-7x)=3 is x=8,x=-1
Solve for x: log_{2}(x^2-7x)=3
The solution is x=8,x=-1