What is the answer to ln(x+11)=ln(x)+4 ?

The answer to ln(x+11)=ln(x)+4 is x=(11)/(e^4-1)

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ln(x+11)=ln(x)+4

ln (x + 11) = ln (x) + 4

x = \frac{11}{e ^{4} - 1}

Decimal

x = 0.20523 \dots

Solution steps

ln (x + 11) = ln (x) + 4

Apply log rules

x + 11 = x e^{4}

Solve

x + 11 = x e^{4} : x = \frac{11}{e ^{4} - 1}

x = \frac{11}{e ^{4} - 1}

Verify Solutions:

x = \frac{11}{e ^{4} - 1}

True

The solution is

x = \frac{11}{e ^{4} - 1}

lo g_{x - 1} (x^{3} - 2 x^{2} + x - 4) = 3

lo g_{3} (T) = \frac{1}{2}

lo g_{3} (x) - lo g_{3} (2 x - 3) = 3

7.1 = - lo g_{10} (x)

ln (x) = m x

What is the answer to ln(x+11)=ln(x)+4 ?
The answer to ln(x+11)=ln(x)+4 is x=(11)/(e^4-1)
Solve for x: ln(x+11)=ln(x)+4
The solution is x=(11)/(e^4-1)