What is the answer to log_{2}((x+1)^2)=-2 ?

The answer to log_{2}((x+1)^2)=-2 is x=-1/2 ,x=-3/2

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log_{2}((x+1)^2)=-2

lo g_{2} ((x + 1)^{2}) = - 2

x = - \frac{1}{2}, x = - \frac{3}{2}

Decimal

x = - 0.5, x = - 1.5

Solution steps

lo g_{2} ((x + 1)^{2}) = - 2

Apply log rules

(x + 1)^{2} = \frac{1}{4}

Solve

(x + 1)^{2} = \frac{1}{4} : x = - \frac{1}{2}, x = - \frac{3}{2}

x = - \frac{1}{2}, x = - \frac{3}{2}

lo g_{4} (2 - x) = 4

y, x = lo g_{5} (- 4 y + 6) + 4

ln (5) + ln (2 x) = 3

- lo g_{10} (x) = 4.1

lo g_{4 x} (x) = \frac{9}{5}

What is the answer to log_{2}((x+1)^2)=-2 ?
The answer to log_{2}((x+1)^2)=-2 is x=-1/2 ,x=-3/2
Solve for x: log_{2}((x+1)^2)=-2
The solution is x=-1/2 ,x=-3/2