What is the answer to -50=10log_{10}(p/1) ?

The answer to -50=10log_{10}(p/1) is p= 1/100000

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-50=10log_{10}(p/1)

- 50 = 10 lo g_{10} (\frac{p}{1})

p = \frac{1}{100000}

Decimal

p = 0.00001

Solution steps

- 50 = 10 lo g_{10} (\frac{p}{1})

Switch sides

10 lo g_{10} (\frac{p}{1}) = - 50

Divide both sides by

10

lo g_{10} (\frac{p}{1}) = - 5

Apply log rules

p = \frac{1}{100000}

Verify Solutions:

p = \frac{1}{100000}

True

The solution is

p = \frac{1}{100000}

lo g_{4} (x) = lo g_{x} (64)

lo g_{11} (7 t + 2) = 2

ln (x + 6) - ln (x) = 1

\frac{1}{5} lo g_{10} (x + 2) - 1 = 0

ln (x) + ln (3) = 4

What is the answer to -50=10log_{10}(p/1) ?
The answer to -50=10log_{10}(p/1) is p= 1/100000
Solve for p: -50=10log_{10}(p/1)
The solution is p= 1/100000