What is the answer to solvefor y,2.16=log_{10}(x)+y1.86 ?

The answer to solvefor y,2.16=log_{10}(x)+y1.86 is y=(2.16-log_{10}(x))^{50/93}

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solvefor y,2.16=log_{10}(x)+y1.86

solve for

y, 2.16 = lo g_{10} (x) + y^{1.86}

y = (2.16 - lo g_{10} (x))^{\frac{50}{93}}

Solution steps

2.16 = lo g_{10} (x) + y^{1.86}

Switch sides

lo g_{10} (x) + y^{1.86} = 2.16

Move

lo g_{10} (x)

to the right side

y^{1.86} = 2.16 - lo g_{10} (x)

Take both sides of the equation to the power of

\frac{50}{93} : y = (2.16 - lo g_{10} (x))^{\frac{50}{93}}

y = (2.16 - lo g_{10} (x))^{\frac{50}{93}}

Verify Solutions:

y = (2.16 - lo g_{10} (x))^{\frac{50}{93}}

True

The solution is

y = (2.16 - lo g_{10} (x))^{\frac{50}{93}}

lo g_{2} (x + 4) = 5

lo g_{2} (7 x + 2) = 3

3 lo g_{4} (2 x - 3) = 6

lo g_{10} (x) = - 0.83879

5 = lo g_{0.25} (x) \times 2

What is the answer to solvefor y,2.16=log_{10}(x)+y1.86 ?
The answer to solvefor y,2.16=log_{10}(x)+y1.86 is y=(2.16-log_{10}(x))^{50/93}