What is the answer to log_{2}(7x+3)=1 ?

The answer to log_{2}(7x+3)=1 is x=-1/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(7x+3)=1

lo g_{2} (7 x + 3) = 1

x = - \frac{1}{7}

Decimal

x = - 0.14285 \dots

Solution steps

lo g_{2} (7 x + 3) = 1

Apply log rules

7 x + 3 = 2

Solve

7 x + 3 = 2 : x = - \frac{1}{7}

x = - \frac{1}{7}

lo g_{5} (x - 2) = 2

lo g_{3} (8 - x) = 3

lo g_{7} (2 x + 5) = 2

lo g_{2} (4 - x) = 3

lo g_{2} (x) = x