What is the answer to 4log_{2}(2x)=4.8 ?

The answer to 4log_{2}(2x)=4.8 is x=(2^{1.2})/2

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4log_{2}(2x)=4.8

4 lo g_{2} (2 x) = 4.8

x = \frac{2 ^{1.2}}{2}

Decimal

x = 1.14869 \dots

Solution steps

4 lo g_{2} (2 x) = 4.8

Divide both sides by

4

lo g_{2} (2 x) = 1.2

Apply log rules

2 x = 2^{1.2}

Solve

2 x = 2^{1.2} : x = \frac{2 ^{1.2}}{2}

x = \frac{2 ^{1.2}}{2}

Verify Solutions:

x = \frac{2 ^{1.2}}{2}

True

The solution is

x = \frac{2 ^{1.2}}{2}

ln ∣ y ∣ = ln ∣ t ∣ + c

- 1 = lo g_{\frac{4}{11}} (x)

ln (\frac{x}{e ^{1}}) = 2

lo g_{b} (53) = 31

lo g_{2} (7 x + 6) = 5

What is the answer to 4log_{2}(2x)=4.8 ?
The answer to 4log_{2}(2x)=4.8 is x=(2^{1.2})/2
Solve for x: 4log_{2}(2x)=4.8
The solution is x=(2^{1.2})/2