What are the solutions to the equation x^2+16x-21=-5 ?

The solutions to the equation x^2+16x-21=-5 are x=4(sqrt(5)-2),x=-4(2+sqrt(5))

Find the zeros of x^2+16x-21=-5

The zeros of x^2+16x-21=-5 are x=4(sqrt(5)-2),x=-4(2+sqrt(5))

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x^{2} + 16 x - 21 = - 5

x = 4 (5 - 2), x = - 4 (2 + 5)

Solution steps

x^{2} + 16 x - 21 = - 5

Move

5

to the left side

x^{2} + 16 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 16) = 85

x_{1, 2} = \frac{- 16 \pm 8 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 8 5}{2 \cdot 1}, x_{2} = \frac{- 16 - 8 5}{2 \cdot 1}

x = \frac{- 16 + 8 5}{2 \cdot 1} : 4 (5 - 2)

x = \frac{- 16 - 8 5}{2 \cdot 1} : - 4 (2 + 5)

The solutions to the quadratic equation are:

x = 4 (5 - 2), x = - 4 (2 + 5)

∣ t ∣ = 2

0. 2^{5}

k = 3 (- \frac{1}{4} k + 3)

(7 + 6)^{2}

\frac{x}{2} - \frac{7}{6} \leq \frac{x}{3} + 1

What are the solutions to the equation x^2+16x-21=-5 ?
The solutions to the equation x^2+16x-21=-5 are x=4(sqrt(5)-2),x=-4(2+sqrt(5))
Find the zeros of x^2+16x-21=-5
The zeros of x^2+16x-21=-5 are x=4(sqrt(5)-2),x=-4(2+sqrt(5))