What is the answer to log_{10}(3x^2)=-2 ?

The answer to log_{10}(3x^2)=-2 is x= 1/(10sqrt(3)),x=-1/(10sqrt(3))

Solve for x: log_{10}(3x^2)=-2

The solution is x= 1/(10sqrt(3)),x=-1/(10sqrt(3))

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lo g_{10} (3 x^{2}) = - 2

x = \frac{1}{10 3}, x = - \frac{1}{10 3}

Decimal

x = 0.05773 \dots, x = - 0.05773 \dots

Solution steps

lo g_{10} (3 x^{2}) = - 2

Apply log rules

3 x^{2} = \frac{1}{100}

Solve

3 x^{2} = \frac{1}{100} : x = \frac{1}{10 3}, x = - \frac{1}{10 3}

x = \frac{1}{10 3}, x = - \frac{1}{10 3}

- \frac{1}{3} = lo g_{27} (x)

lo g_{10} (3 x^{2} + 25) = 2

9 = y + lo g_{e} (y - 8)

y, lo g_{4} (x - 2 y) = 3

lo g_{10} (x) = 4 lo g_{10} (5)

What is the answer to log_{10}(3x^2)=-2 ?
The answer to log_{10}(3x^2)=-2 is x= 1/(10sqrt(3)),x=-1/(10sqrt(3))
Solve for x: log_{10}(3x^2)=-2
The solution is x= 1/(10sqrt(3)),x=-1/(10sqrt(3))