What is the answer to solvefor y,x=2ln(3-y) ?

The answer to solvefor y,x=2ln(3-y) is y=-e^{x/2}+3

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solvefor y,x=2ln(3-y)

solve for

y, x = 2 ln (3 - y)

y = - e^{\frac{x}{2}} + 3

Solution steps

x = 2 ln (3 - y)

Switch sides

2 ln (3 - y) = x

Divide both sides by

2

ln (3 - y) = \frac{x}{2}

Apply log rules

3 - y = e^{\frac{x}{2}}

Solve

3 - y = e^{\frac{x}{2}} : y = - e^{\frac{x}{2}} + 3

y = - e^{\frac{x}{2}} + 3

Verify Solutions:

y = - e^{\frac{x}{2}} + 3

True

The solution is

y = - e^{\frac{x}{2}} + 3

5 ln (x) + 5 = 0

ln (x + 1 - \frac{x}{4}) = 0

\frac{1}{5} lo g_{10} (x + 2) - 1 = 0

lo g_{10} (6 x) = 216

85 = - 591 lo g_{10} (x)

What is the answer to solvefor y,x=2ln(3-y) ?
The answer to solvefor y,x=2ln(3-y) is y=-e^{x/2}+3