What is the answer to solvefor x,5x+3ln(x-4)=25 ?

The answer to solvefor x,5x+3ln(x-4)=25 is x=(3\W_{0}((5e^{5/3})/3)+20)/(5)

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solvefor x,5x+3ln(x-4)=25

solve for

x, 5 x + 3 ln (x - 4) = 25

x = \frac{3 W _{0} ( \frac{5 e ^{\frac{5}{3}}}{3} ) + 20}{5}

Decimal

x = 5

Solution steps

5 x + 3 ln (x - 4) = 25

Move

5 x

to the right side

3 ln (x - 4) = 25 - 5 x

Divide both sides by

3

ln (x - 4) = \frac{25 - 5 x}{3}

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x - 4)} = e^{\frac{25 - 5 x}{3}}

Simplify

e^{l n (x - 4)} : x - 4

x - 4 = e^{\frac{25 - 5 x}{3}}

Solve

x - 4 = e^{\frac{25 - 5 x}{3}} : x = \frac{3 W _{0} ( \frac{5 e ^{\frac{5}{3}}}{3} ) + 20}{5}

x = \frac{3 W _{0} ( \frac{5 e ^{\frac{5}{3}}}{3} ) + 20}{5}

Verify Solutions:

x = \frac{3 W _{0} ( \frac{5 e ^{\frac{5}{3}}}{3} ) + 20}{5}

True

The solution is

x = \frac{3 W _{0} ( \frac{5 e ^{\frac{5}{3}}}{3} ) + 20}{5}

10 lo g_{10} (\frac{x}{20}) = 5

lo g_{a} (16) = \frac{1}{2}

lo g_{3} (5) + lo g_{3} (x - 4) = 2

ln (x) + ln (x - 2) = ln (2 x)

10 lo g_{10} (x) = 3

What is the answer to solvefor x,5x+3ln(x-4)=25 ?
The answer to solvefor x,5x+3ln(x-4)=25 is x=(3\W_{0}((5e^{5/3})/3)+20)/(5)