What is the answer to solvefor f,f^{-1}(x)=ln(x) ?

The answer to solvefor f,f^{-1}(x)=ln(x) is f= x/(ln(x));\quad x\ne 1

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solvefor f,f^{-1}(x)=ln(x)

solve for

f, f^{- 1} (x) = ln (x)

f = \frac{x}{ln ( x )}; x \neq = 1

Solution steps

f^{- 1} (x) = ln (x)

Refine

\frac{x}{f} = ln (x)

Multiply both sides by

f

x = ln (x) f

Switch sides

ln (x) f = x

Divide both sides by

ln (x); x \neq = 1

f = \frac{x}{ln ( x )}; x \neq = 1

lo g_{\frac{1}{2}} (1 - 3 x) = 2

- 20 = 10 \times lo g_{10} (x)

y, ∣ y ∣ = x

∣ 6 - 6 x ∣ = 19

24 = ∣ 9 x + 8 ∣ 8

What is the answer to solvefor f,f^{-1}(x)=ln(x) ?
The answer to solvefor f,f^{-1}(x)=ln(x) is f= x/(ln(x));\quad x\ne 1