What is the answer to x^3-3x^2+2x=|x+1|-1 ?

The answer to x^3-3x^2+2x=|x+1|-1 is x=0\lor x=(3-sqrt(5))/2 \lor x=(3+sqrt(5))/2

Solve for x: x^3-3x^2+2x=|x+1|-1

The solution is x=0\lor x=(3-sqrt(5))/2 \lor x=(3+sqrt(5))/2

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x^{3} - 3 x^{2} + 2 x = ∣ x + 1 ∣ - 1

x = 0 or x = \frac{3 - 5}{2} or x = \frac{3 + 5}{2}

Decimal

x = 0, x = 0.38196 \dots, x = 2.61803 \dots

Solution steps

x^{3} - 3 x^{2} + 2 x = ∣ x + 1 ∣ - 1

Find positive and negative intervals

x < - 1, x \geq - 1

Solve the inequality for each interval

No Solution or (x = 0 or x = \frac{3 - 5}{2} or x = \frac{3 + 5}{2})

x = 0 or x = \frac{3 - 5}{2} or x = \frac{3 + 5}{2}

- 8 + ∣ 3 x + 9 ∣ = 7

8 + ∣ 3 x + 9 ∣ = 7

∣ 2 x - 1 ∣ - 4 = 3

x + ∣ x ∣ = y + ∣ y ∣

∣ x - 3 ∣ - ∣ x + 2 ∣ = 5

What is the answer to x^3-3x^2+2x=|x+1|-1 ?
The answer to x^3-3x^2+2x=|x+1|-1 is x=0\lor x=(3-sqrt(5))/2 \lor x=(3+sqrt(5))/2
Solve for x: x^3-3x^2+2x=|x+1|-1
The solution is x=0\lor x=(3-sqrt(5))/2 \lor x=(3+sqrt(5))/2