What is (6-x)/(x+2)>1 ?

The solution to (6-x)/(x+2)>1 is -2<x<2

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(6-x)/(x+2)>1

\frac{6 - x}{x + 2} > 1

- 2 < x < 2

Interval Notation

(- 2, 2)

Solution steps

\frac{6 - x}{x + 2} > 1

Rewrite in standard form

\frac{- 2 x + 4}{x + 2} > 0

Factor

\frac{- 2 x + 4}{x + 2} : \frac{- 2 ( x - 2 )}{x + 2}

\frac{- 2 ( x - 2 )}{x + 2} > 0

Multiply both sides by

- 1

(reverse the inequality)

\frac{( - 2 ( x - 2 ) ) ( - 1 )}{x + 2} < 0 \cdot (- 1)

Simplify

\frac{2 ( x - 2 )}{x + 2} < 0

Divide both sides by

2

\frac{\frac{2 ( x - 2 )}{x + 2}}{2} < \frac{0}{2}

Simplify

\frac{x - 2}{x + 2} < 0

Identify the intervals

- 2 < x < 2

x^{3} - 49 x

30 π a^{2} b^{3} - 15 πa b^{2} + 10 π b^{4}

64 x^{3} - 144 x^{2} + 92 x - 15

∣ a + 9 ∣ + 2 = 6

8 x - 20 = 3 x + 10