What is the answer to |-x^2+7x-4|=6 ?

The answer to |-x^2+7x-4|=6 is x=-(-7+sqrt(57))/2 \lor x=2\lor x=5\lor x=(7+sqrt(57))/2

Solve for x: |-x^2+7x-4|=6

The solution is x=-(-7+sqrt(57))/2 \lor x=2\lor x=5\lor x=(7+sqrt(57))/2

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- x^{2} + 7 x - 4 = 6

x = - \frac{- 7 + 57}{2} or x = 2 or x = 5 or x = \frac{7 + 57}{2}

Decimal

x = - 0.27491 \dots, x = 2, x = 5, x = 7.27491 \dots

Solution steps

- x^{2} + 7 x - 4 = 6

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

- x^{2} + 7 x - 4 = - 6 or - x^{2} + 7 x - 4 = 6

- x^{2} + 7 x - 4 = - 6 or - x^{2} + 7 x - 4 = 6

(x = - \frac{- 7 + 57}{2} or x = \frac{7 + 57}{2}) or (x = 2 or x = 5)

x = - \frac{- 7 + 57}{2} or x = 2 or x = 5 or x = \frac{7 + 57}{2}

∣ 6 x - 9 ∣ = - 27

a, ∣ 2 + a ∣ + b = - 1

∣ 2 x ∣ = 84

x - ∣ 2 x - 1 ∣ = 4 x + 2

- 3 ∣ m ∣ = - 9

What is the answer to |-x^2+7x-4|=6 ?
The answer to |-x^2+7x-4|=6 is x=-(-7+sqrt(57))/2 \lor x=2\lor x=5\lor x=(7+sqrt(57))/2
Solve for x: |-x^2+7x-4|=6
The solution is x=-(-7+sqrt(57))/2 \lor x=2\lor x=5\lor x=(7+sqrt(57))/2