What is the answer to |4x+3|+|12x+9|=48 ?

The answer to |4x+3|+|12x+9|=48 is x=-15/4 \lor x= 9/4

Solve for x: |4x+3|+|12x+9|=48

The solution is x=-15/4 \lor x= 9/4

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∣ 4 x + 3 ∣ + ∣ 12 x + 9 ∣ = 48

x = - \frac{15}{4} or x = \frac{9}{4}

Decimal

x = - 3.75, x = 2.25

Solution steps

∣ 4 x + 3 ∣ + ∣ 12 x + 9 ∣ = 48

Find positive and negative intervals

x < - \frac{3}{4}, x \geq - \frac{3}{4}

Solve the inequality for each interval

x = - \frac{15}{4} or x = \frac{9}{4}

x^{2} + 3 x - 1 = 2 - x

∣ X + 5 ∣ = - 15

∣ 2 x - 11 ∣ = 6

x^{2} = x^{2} - 5 x + 3

2 ∣ z ∣ = ∣ z - 2 ∣

What is the answer to |4x+3|+|12x+9|=48 ?
The answer to |4x+3|+|12x+9|=48 is x=-15/4 \lor x= 9/4
Solve for x: |4x+3|+|12x+9|=48
The solution is x=-15/4 \lor x= 9/4