What is the answer to |3m-2|=m^2 ?

The answer to |3m-2|=m^2 is m=(-3-sqrt(17))/2 \lor m=(-3+sqrt(17))/2 \lor m=1\lor m=2

Solve for m: |3m-2|=m^2

The solution is m=(-3-sqrt(17))/2 \lor m=(-3+sqrt(17))/2 \lor m=1\lor m=2

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∣ 3 m - 2 ∣ = m^{2}

m = \frac{- 3 - 17}{2} or m = \frac{- 3 + 17}{2} or m = 1 or m = 2

Decimal

m = - 3.56155 \dots, m = 0.56155 \dots, m = 1, m = 2

Solution steps

∣ 3 m - 2 ∣ = m^{2}

Find positive and negative intervals

m < \frac{2}{3}, m \geq \frac{2}{3}

Solve the inequality for each interval

(m = \frac{- 3 - 17}{2} or m = \frac{- 3 + 17}{2}) or (m = 1 or m = 2)

m = \frac{- 3 - 17}{2} or m = \frac{- 3 + 17}{2} or m = 1 or m = 2

∣ 7 x ∣ = 4 + x

∣ x - 1 ∣ ∣ x + 2 ∣ = 3

9 - 2 ∣ 4 x - 2 ∣ = 7

42 - ∣ x ∣ = 15

∣ 2 x - 5 ∣ = - 8

What is the answer to |3m-2|=m^2 ?
The answer to |3m-2|=m^2 is m=(-3-sqrt(17))/2 \lor m=(-3+sqrt(17))/2 \lor m=1\lor m=2
Solve for m: |3m-2|=m^2
The solution is m=(-3-sqrt(17))/2 \lor m=(-3+sqrt(17))/2 \lor m=1\lor m=2