What is the answer to |10x+1|=41 ?

The answer to |10x+1|=41 is x=-21/5 \lor x=4

Solve for x: |10x+1|=41

The solution is x=-21/5 \lor x=4

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∣ 10 x + 1 ∣ = 41

x = - \frac{21}{5} or x = 4

Decimal

x = - 4.2, x = 4

Solution steps

∣ 10 x + 1 ∣ = 41

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

10 x + 1 = - 41 or 10 x + 1 = 41

10 x + 1 = - 41 or 10 x + 1 = 41

x = - \frac{21}{5} or x = 4

∣ 6 x - 2 ∣ - 3 = - 3

y, x = ∣ y - 6 ∣ + 7

∣ x - 1 ∣ = ∣ x + 3 ∣

∣ x + 1 ∣ + ∣ 3 x - 2 ∣ = 2

∣ 4 n - 15 ∣ = ∣ n ∣