What is the answer to (x-3)^2-12|x-3|+35=0 ?

The answer to (x-3)^2-12|x-3|+35=0 is x=-4\lor x=-2\lor x=8\lor x=10

Solve for x: (x-3)^2-12|x-3|+35=0

The solution is x=-4\lor x=-2\lor x=8\lor x=10

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(x - 3)^{2} - 12 ∣ x - 3 ∣ + 35 = 0

x = - 4 or x = - 2 or x = 8 or x = 10

Solution steps

(x - 3)^{2} - 12 ∣ x - 3 ∣ + 35 = 0

Find positive and negative intervals

x < 3, x \geq 3

Solve the inequality for each interval

(x = - 4 or x = - 2) or (x = 8 or x = 10)

x = - 4 or x = - 2 or x = 8 or x = 10

- 11 = - 2 ∣ 5 d - 1 ∣ - 3

x^{3} + x - 1 = x + 1

∣ x + 1 ∣ + ∣ 2 x - 3 ∣ = 8

∣ 3 x + 9 ∣ - 9 = 40

∣ x + 1 ∣ = ∣ x - 3 ∣

What is the answer to (x-3)^2-12|x-3|+35=0 ?
The answer to (x-3)^2-12|x-3|+35=0 is x=-4\lor x=-2\lor x=8\lor x=10
Solve for x: (x-3)^2-12|x-3|+35=0
The solution is x=-4\lor x=-2\lor x=8\lor x=10