What is the answer to |x^2+4x|=12 ?

The answer to |x^2+4x|=12 is x=-6\lor x=2

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|x^2+4x|=12

x^{2} + 4 x = 12

x = - 6 or x = 2

Solution steps

x^{2} + 4 x = 12

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 4 x = - 12 or x^{2} + 4 x = 12

x^{2} + 4 x = - 12 or x^{2} + 4 x = 12

No Solution or (x = - 6 or x = 2)

x = - 6 or x = 2

x^{3} ∣ x ∣ = 8 x

∣ x - 6 ∣ = 3 x

∣ 3 g ∣ - 4 = 11

∣ - x + 3 ∣ = 2

- 3 ∣ 2 w ∣ = - 12