What is the answer to |x^2-2x-4|=0 ?

The answer to |x^2-2x-4|=0 is x=1-sqrt(5)\lor x=1+sqrt(5)

Solve for x: |x^2-2x-4|=0

The solution is x=1-sqrt(5)\lor x=1+sqrt(5)

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x^{2} - 2 x - 4 = 0

x = 1 - 5 or x = 1 + 5

Decimal

x = - 1.23606 \dots, x = 3.23606 \dots

Solution steps

x^{2} - 2 x - 4 = 0

Apply absolute rule: If

∣ u ∣ = 0

then

u = 0

x^{2} - 2 x - 4 = 0

x^{2} - 2 x - 4 = 0 : x = 1 + 5, x = 1 - 5

x = 1 - 5 or x = 1 + 5

∣ z ∣ = ∣ z - 2 ∣

∣ 4 n - 1 ∣ = - 6

∣ x ∣ - 1 = 2 x + 1

x, 26 = ∣ x - 15 ∣

14 - ∣ x + 8 ∣ = 5

What is the answer to |x^2-2x-4|=0 ?
The answer to |x^2-2x-4|=0 is x=1-sqrt(5)\lor x=1+sqrt(5)
Solve for x: |x^2-2x-4|=0
The solution is x=1-sqrt(5)\lor x=1+sqrt(5)