What is (x+1)(x-1)(3x-6)>0 ?

The solution to (x+1)(x-1)(3x-6)>0 is -1 2

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(x+1)(x-1)(3x-6)>0

(x + 1) (x - 1) (3 x - 6) > 0

- 1 < x < 1 or x > 2

Interval Notation

(- 1, 1) \cup (2, \infty)

Solution steps

(x + 1) (x - 1) (3 x - 6) > 0

Rewrite in standard form

x^{3} - 2 x^{2} - x + 2 > 0

Factor

x^{3} - 2 x^{2} - x + 2 : (x - 2) (x + 1) (x - 1)

(x - 2) (x + 1) (x - 1) > 0

Identify the intervals

- 1 < x < 1 or x > 2

3 (- \frac{2}{5})^{0}

- (x + 2 y)^{2} + 16 (x + y)^{2}

2 (v - 4) - 10 = - 2 (- 1 + 4 v)

1 + \frac{1}{16}

\frac{n ^{2}}{n ^{4}}

What is (x+1)(x-1)(3x-6)>0 ?
The solution to (x+1)(x-1)(3x-6)>0 is -1<x<1\lor x>2