What is the answer to |2r+5|=|7r-32| ?

The answer to |2r+5|=|7r-32| is r=3\lor r= 37/5

Solve for r: |2r+5|=|7r-32|

The solution is r=3\lor r= 37/5

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∣ 2 r + 5 ∣ = ∣ 7 r - 32 ∣

r = 3 or r = \frac{37}{5}

Decimal

r = 3, r = 7.4

Solution steps

∣ 2 r + 5 ∣ = ∣ 7 r - 32 ∣

Find positive and negative intervals

r < - \frac{5}{2}, - \frac{5}{2} \leq r < \frac{32}{7}, r \geq \frac{32}{7}

Solve the inequality for each interval

No Solution or r = 3 or r = \frac{37}{5}

r = 3 or r = \frac{37}{5}

∣ 2 x + 3 ∣ = 17

∣ 1 - 3 x ∣ = ∣ 4 x + 5 ∣

2 ∣ x - 3 ∣ + 2 = 5 x - 6

x^{2} - 2 x - 3 = 0

∣ x + 3 ∣ - 2 = ∣ x ∣ + 2 x

What is the answer to |2r+5|=|7r-32| ?
The answer to |2r+5|=|7r-32| is r=3\lor r= 37/5
Solve for r: |2r+5|=|7r-32|
The solution is r=3\lor r= 37/5