What is the answer to |x-2|+|x+8|=10 ?

The answer to |x-2|+|x+8|=10 is -8<= x<= 2

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|x-2|+|x+8|=10

∣ x - 2 ∣ + ∣ x + 8 ∣ = 10

- 8 \leq x \leq 2

Solution steps

∣ x - 2 ∣ + ∣ x + 8 ∣ = 10

Find positive and negative intervals

x < - 8, - 8 \leq x < 2, x \geq 2

Solve the inequality for each interval

No Solution or - 8 \leq x < 2 or x = 2

Merge Overlapping Intervals

- 8 \leq x \leq 2

∣ t ∣ + 1 = - 17

t - \frac{5}{8} = \frac{1}{56}

y, h = - ∣ y - 2 ∣

∣ x + y ∣ = ∣ x ∣ + ∣ y ∣

(z^{3}) - ∣ z ∣ = 0

What is the answer to |x-2|+|x+8|=10 ?
The answer to |x-2|+|x+8|=10 is -8<= x<= 2
Solve for x: |x-2|+|x+8|=10
The solution is -8<= x<= 2