What is the answer to |x^2+7x+14|=4 ?

The answer to |x^2+7x+14|=4 is x=-5\lor x=-2

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|x^2+7x+14|=4

x^{2} + 7 x + 14 = 4

x = - 5 or x = - 2

Solution steps

x^{2} + 7 x + 14 = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 7 x + 14 = - 4 or x^{2} + 7 x + 14 = 4

x^{2} + 7 x + 14 = - 4 or x^{2} + 7 x + 14 = 4

No Solution or (x = - 5 or x = - 2)

x = - 5 or x = - 2

∣ 2 x - 1 ∣ + x = 8

- 2 ∣ 7 - 3 x ∣ - 6 = - 14

x^{2} + 5 x = ∣ 4 - x ∣

- 3 ∣ y - 4 ∣ = 6

- x^{2} + 5 x - 6 = ∣ x - 3 ∣ - 9

What is the answer to |x^2+7x+14|=4 ?
The answer to |x^2+7x+14|=4 is x=-5\lor x=-2
Solve for x: |x^2+7x+14|=4
The solution is x=-5\lor x=-2