What are the solutions to the equation y^2-18y=-82 ?

The solutions to the equation y^2-18y=-82 are y=9+i,y=9-i

Find the zeros of y^2-18y=-82

The zeros of y^2-18y=-82 are y=9+i,y=9-i

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y^{2} - 18 y = - 82

y = 9 + i, y = 9 - i

Solution steps

y^{2} - 18 y = - 82

Move

82

to the left side

y^{2} - 18 y + 82 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 82}{2 \cdot 1}

Simplify

(- 18)^{2} - 4 \cdot 1 \cdot 82 : 2 i

y_{1, 2} = \frac{- ( - 18 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 18 ) + 2 i}{2 \cdot 1}, y_{2} = \frac{- ( - 18 ) - 2 i}{2 \cdot 1}

y = \frac{- ( - 18 ) + 2 i}{2 \cdot 1} : 9 + i

y = \frac{- ( - 18 ) - 2 i}{2 \cdot 1} : 9 - i

The solutions to the quadratic equation are:

y = 9 + i, y = 9 - i

\frac{x}{5} = - 6

\frac{1}{4} (x - 9) < x + 12

\frac{1}{10} (a + 1) = \frac{1}{6} (2 - a)

\frac{2}{3 x - 4} > 5

2 x^{2} + 14 x - 36

What are the solutions to the equation y^2-18y=-82 ?
The solutions to the equation y^2-18y=-82 are y=9+i,y=9-i
Find the zeros of y^2-18y=-82
The zeros of y^2-18y=-82 are y=9+i,y=9-i