What is the answer to |x+1|=(x-41)^2 ?

The answer to |x+1|=(x-41)^2 is x=35\lor x=48

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|x+1|=(x-41)^2

∣ x + 1 ∣ = (x - 41)^{2}

x = 35 or x = 48

Solution steps

∣ x + 1 ∣ = (x - 41)^{2}

Find positive and negative intervals

x < - 1, x \geq - 1

Solve the inequality for each interval

No Solution or (x = 35 or x = 48)

x = 35 or x = 48

10 - ∣ 3 x + 2 ∣ = 7

∣ 2 x + 5 ∣ = 5

∣ 2 x + 5 ∣ = 2

∣ y + 4 ∣ = 8

2 + ∣ 3 x - 2 ∣ = 18

What is the answer to |x+1|=(x-41)^2 ?
The answer to |x+1|=(x-41)^2 is x=35\lor x=48
Solve for x: |x+1|=(x-41)^2
The solution is x=35\lor x=48