What are the solutions to the equation (x-3)^2=-16 ?

The solutions to the equation (x-3)^2=-16 are x=4i+3,x=-4i+3

Find the zeros of (x-3)^2=-16

The zeros of (x-3)^2=-16 are x=4i+3,x=-4i+3

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(x - 3)^{2} = - 16

x = 4 i + 3, x = - 4 i + 3

Solution steps

(x - 3)^{2} = - 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = - 16 : x = 4 i + 3

Solve

x - 3 = - - 16 : x = - 4 i + 3

The solutions to the quadratic equation are:

x = 4 i + 3, x = - 4 i + 3

∣ 5 x + 1 ∣ - 8 = 4 x

x^{2} \leq 6 - x

3 (\frac{1}{3})

a^{2} - 9 a + 14

\frac{( 2 ^{4} ) ^{2}}{4 ^{2}}

What are the solutions to the equation (x-3)^2=-16 ?
The solutions to the equation (x-3)^2=-16 are x=4i+3,x=-4i+3
Find the zeros of (x-3)^2=-16
The zeros of (x-3)^2=-16 are x=4i+3,x=-4i+3